Question:
In the given circuit the input voltage Vin is shown in figure. The cut-in voltage of p–n junction diode
(D1 or D2) is 0.6 V. Which of the following output voltage (V0) waveform across the diode is correct?
In the given circuit the input voltage Vin is shown in figure. The cut-in voltage of p–n junction diode
(D1 or D2) is 0.6 V. Which of the following output voltage (V0) waveform across the diode is correct?
Updated On: Mar 19, 2025
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The Correct Option is A
Solution and Explanation
Till |V|≤0.6 V
|V0|=|V|
So, correct graph is D.
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Concepts Used:
P-n Junction
A P-N junction is an interface or a boundary between two semiconductor material types, namely the p-type and the n-type, inside a semiconductor.
Biasing conditions for the p-n Junction Diode:
in p-n junction diode two operating regions are there:
- P-type
- N-type
There are three biasing conditions for p-n junction diode are as follows:
- Zero bias: When there is no external voltage applied to the p-n junction diode.
- Forward bias: P-type is connected to positive terminal of the voltage potential while n-type is connected to the negative terminal.
- Reverse bias: P-type is connected to negative terminal of the voltage potential while n-type is connected to the positive terminal.