Question

In the given circuit, A.C. source is given by: \[ V = 282 \sin (100 \pi t) \text{ volt} \] The internal resistance of the source is \( 2000 \, \Omega \). 

 Find out: 

(i) rms value of source voltage
(ii)inductive reactance of the circuit
(iii) impedance of the circuit
 

Hint:

RMS voltage is obtained by dividing peak voltage by \( \sqrt{2} \).

Answer 1

(i) RMS Value of Source Voltage The given voltage is in peak form: \[ V_{\text{peak}} = 282 \text{ V} \] \[ V_{\text{rms}} = \frac{V_{\text{peak}}}{\sqrt{2}} \] \[ = \frac{282}{\sqrt{2}} = 199.5 \text{ V} \] \[ \boxed{199.5 \text{ V}} \]