




To solve this sequence of reactions, let's analyze each step:
The substrate is a cyclic compound with chlorine and bromine substituents. It reacts with sodium (Na) in the presence of diethyl ether (Et2O), which is typically used for a Wurtz reaction. This reaction will form an intermediate where two halogen atoms are removed, and a new carbon-carbon bond is formed, resulting in a ring structure with two additional carbon atoms.
The intermediate compound A is then treated with magnesium (Mg) in diethyl ether to form a Grignard reagent. The Grignard reagent is represented as RMgX where R is the organic group.
The Grignard reagent reacts with D2O (deuterium oxide) to replace the MgBr part with a deuterium atom (D), resulting in compound B, which is a deuterated hydrocarbon.
The compound A also reacts simultaneously via CoF2-catalyzed reaction to form compound C. CoF2 is used as a catalyst in some polymerization reactions, hinting that a new product formation may involve a fluorinated derivative or similar activity.
The reactions above indicate that compound B is the deuterated cyclopropane and compound C may involve some modifications due to CoF2. Based on the given options and the typical reactivities, the product matches the structure described by:
Thus, the major products B and C are identified as the ones shown in the correct answer option above.

Thus the correct answer is Option 1.
MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K.
MX(s) $\rightleftharpoons M^{+(aq) }+ X^{-}(aq)$; $K_{sp} = 10^{-10}$
If the standard reduction potential for $M^{+}(aq) + e^{-} \rightarrow M(s)$ is $(E^{\circ}_{M^{+}/M}) = 0.79$ V, then the value of the standard reduction potential for the metal/metal insoluble salt electrode $E^{\circ}_{X^{-}/MX(s)/M}$ is ____________ mV. (nearest integer)
[Given : $\frac{2.303 RT}{F} = 0.059$ V]
An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :
