




The correct answer is (3) Butanal and acetaldehyde.
Explanation: Ozonolysis of 2-hexene, followed by a reductive workup with water, cleaves the double bond. * The fragment CH3-CH= becomes CH3-CHO (acetaldehyde). * The fragment =CH-CH2-CH2-CH3 becomes O=CH-CH2-CH2-CH3 (butanal). Therefore, the products are butanal and acetaldehyde.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)