
From the figure, the base half-angle of the cone (angle ACD) is 60°, with the height \(AD=30\) cm. Instead of finding the base radius directly from the tangent ratio, find the slant length \(AC\) first using the sine ratio, then obtain the radius from the cosine ratio.
\[\sin60^{\circ}=\frac{AD}{AC} \implies AC=\frac{30}{\sin60^{\circ}}=\frac{30}{\frac{\sqrt3}{2}}=\frac{60}{\sqrt3}=20\sqrt3\text{ cm}\]
\[\cos60^{\circ}=\frac{DC}{AC} \implies DC=AC\times\cos60^{\circ}=20\sqrt3\times\frac12=10\sqrt3\text{ cm}\]
So the base radius of the cone is \(10\sqrt3\) cm, and its volume is:
\[V=\frac13\pi r^{2}h=\frac13\pi(10\sqrt3)^{2}(30)=\frac13\pi(300)(30)=3000\pi\text{ cm}^{3}\]
The volume of the cone is \(3000\pi\text{ cm}^{3}\).
Hence, the correct answer is Option A: \(3000\pi \text{ cm}^3\).