Question:
In the equilibrium, \( AB \rightleftharpoons A + B \), if the equilibrium concentration of A is double, then the equilibrium concentration of B will be:
In the equilibrium, \( AB \rightleftharpoons A + B \), if the equilibrium concentration of A is double, then the equilibrium concentration of B will be:
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When equilibrium concentrations of one reactant change, the equilibrium concentrations of other substances adjust to maintain the equilibrium constant.
Updated On: Apr 23, 2025
- Half
- Twice
- \( \frac{1}{4} \)
- \( \frac{1}{8} \)
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The Correct Option is A
Solution and Explanation
In equilibrium reactions, the concentrations of the reactants and products are related by the equilibrium constant. If the concentration of \( A \) is doubled, this means that the amount of \( B \) produced must decrease because of the conservation of mass. Therefore, the equilibrium concentration of \( B \) will be half of the initial concentration of \( B \). Thus, the correct answer is option (A).
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