Question:
In the disproportionation reaction of nitrous acid, X is formed along with nitric acid and water. X can also be obtained by the reaction of:
In the disproportionation reaction of nitrous acid, X is formed along with nitric acid and water. X can also be obtained by the reaction of:
Show Hint
Remember the reactions of metals with dilute and concentrated nitric acid. The products formed depend on the metal and the concentration of the acid.
Updated On: Mar 15, 2025
- Zn + dil. HNO\(_3\)
- Zn + Conc. HNO\(_3\)
- Cu + dil. HNO\(_3\)
- Cu + Conc. HNO\(_3\)
Show Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
1. Disproportionation of nitrous acid (HNO\(_2\)):
Cu + dil. HNO\(_3\).
\( 3 \text{HNO}_2 \rightarrow \text{HNO}_3 + 2 \text{NO} + \text{H}_2\text{O} \)
Thus, X is NO (nitric oxide).
2. Reaction of metals with nitric acid: Zinc (Zn):\( \text{Zn} + \text{dil. HNO}_3 \rightarrow \text{Zn(NO}_3)_2 + \text{NH}_4\text{NO}_3 + \text{H}_2\text{O} \) (Ammonium nitrate is formed)
\( \text{Zn} + \text{Conc. HNO}_3 \rightarrow \text{Zn(NO}_3)_2 + \text{NO}_2 + \text{H}_2\text{O} \) (Nitrogen dioxide is formed)
Copper (Cu):\( 3 \text{Cu} + 8 \text{dil. HNO}_3 \rightarrow 3 \text{Cu(NO}_3)_2 + 2 \text{NO} + 4 \text{H}_2\text{O} \) (Nitric oxide is formed)
\( \text{Cu} + 4 \text{Conc. HNO}_3 \rightarrow \text{Cu(NO}_3)_2 + 2 \text{NO}_2 + 2 \text{H}_2\text{O} \) (Nitrogen dioxide is formed)
From the above reactions, we can see that:
Cu + dil. HNO\(_3\) produces NO (nitric oxide), which is X.
Therefore, X can also be obtained by the reaction of Cu + dil. HNO\(_3\).
Final Answer:Cu + dil. HNO\(_3\).
Was this answer helpful?
0
0
Top AP EAMCET Chemistry Questions
- If the $pK_a$ of acetic acid and $pK_b$ of dimethylamine are $4.76$ and $3.26$ respectively, the pH of dimethyl ammonium acetate solution is
- In the first order thermal decomposition of $C _{2} H _{5} I (g) \longrightarrow C _{2} H _{4}(g)+ HI (g)$, the reactant in the beginning exerts a pressure of $2$ bar in a closed vessel at $600 \,K$. If the partial pressure of the reactant is $0.1$ bar after $1000$ minutes at the same temperature the rate constant in $\min ^{-1}$ is $(\log 2=0.3010)$
- Isopropyl benzene on aerial oxidation followed by acid hydrolysis of the resulting compound yields
- Sodium nitrite is reacted with $H_2SO_4$ to form $NaHSO_4, HNO_3$, water and $X$. Gold is dissolved in aqua-regia to form water, $AuCl^{-}_4$ and $Y. X$ and $Y$ are respectively
- The average translational kinetic energy of a molecule in a gas becomes equal to $0.69\, eV$ at a temperature about [Boltzmann constant = $1.38 \times 10^{-23} \; J \; K^{-1}$]
View More Questions
Top AP EAMCET Group 15 Elements Questions
- Sodium nitrite is reacted with $H_2SO_4$ to form $NaHSO_4, HNO_3$, water and $X$. Gold is dissolved in aqua-regia to form water, $AuCl^{-}_4$ and $Y. X$ and $Y$ are respectively
- White phosphorus is heated with concentrated $NaOH$ in $CO _{2}$ atmosphere to form a gas $A$ and compound $B$. When $A$ is bubbled into aqueous $CuSO _{4}$ solution copper phosphide and $C$ are formed, $B$ and $C$ are respectively
- Which of the following statements are correct? I) $\ce{P_4}$ molecule is very reactive because of angular strain II) The basicity of $\ce{H_3PO_3}$ is $3$ III) In gas phase, all $\ce{P-Cl}$ bonds of $\ce{PCl_5}$ have same bond length IV) In solid state.$ \ce{PCl_5}$ exists as an ionic solid, in which anion $\ce{[PCl_6]^{-}}$ has octahedral and cation $\ce{[PCl_4]^{+}}$ has tetrahedral shape.
- Which one of the following is not present in the nitration mixture?
- The total number of products formed in the following reactions:
LiNO\(_3\) \(\xrightarrow{\Delta}\) Products NaNO\(_3\) \(\xrightarrow{\Delta}\) Products Be(NO\(_3\))\(_2\) \(\xrightarrow{\Delta}\) Products
View More Questions
Top AP EAMCET Questions
- If $\int \cos x . \cos 2x . \cos 5x dx = A \; \sin 2x + B \sin 4x + C \sin 6x + D \sin 8x + k $ (where $k$ is the arbitrary constant of integration), then $\frac{1}{B} + \frac{1}{C} = $
- If $k$ is one of the roots of the equation $x^2 - 25x + 24 = 0 $ such that $A = \begin{bmatrix}1&2&1\\ 3&2&3\\ 1&1&k\end{bmatrix} $ is a non-singular matrix, then $A^{-1}$ =
- If only $\frac{1}{51}^{th}$ ot the main current is to be passed through a galvanometer then the shunt required is $R_1$ and if only $\frac{1}{11}^{th}$ of the main voltage is to be developed across the galvanometer, then the resistance required is $R_2$. Then $\frac{R_2}{R_1} =$
- If $p$ and $q$ are respectively the global maximum and global minimum of the function $f(x) = x^2 e^{2x}$ on the interval $[-2, 2]$ , then $pe^{-4} + qe^4 = $
- If $\displaystyle\sum^n_{k - 1} \tan^{-1} \left( \frac{1}{k^2 + k + 1} \right) = \tan^{-1} (\theta) $ , then $\theta$ =
View More Questions