Question:
The total number of products formed in the following reactions:
LiNO\(_3\) \(\xrightarrow{\Delta}\) Products
NaNO\(_3\) \(\xrightarrow{\Delta}\) Products
Be(NO\(_3\))\(_2\) \(\xrightarrow{\Delta}\) Products
The total number of products formed in the following reactions:
LiNO\(_3\) \(\xrightarrow{\Delta}\) Products NaNO\(_3\) \(\xrightarrow{\Delta}\) Products Be(NO\(_3\))\(_2\) \(\xrightarrow{\Delta}\) Products
LiNO\(_3\) \(\xrightarrow{\Delta}\) Products NaNO\(_3\) \(\xrightarrow{\Delta}\) Products Be(NO\(_3\))\(_2\) \(\xrightarrow{\Delta}\) Products
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Remember the thermal decomposition reactions of alkali metal and alkaline earth metal nitrates.
Updated On: Mar 18, 2026
- 7
- 9
- 6
- 8
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Verified By Collegedunia
The Correct Option is D
Solution and Explanation
1. Decomposition of LiNO\(_3\): * 4LiNO\(_3\) \(\xrightarrow{\Delta}\) 2Li\(_2\)O + 4NO\(_2\) + O\(_2\) * Products: Li\(_2\)O, NO\(_2\), O\(_2\) (3 products)
2. Decomposition of NaNO\(_3\): * 2NaNO\(_3\) \(\xrightarrow{\Delta}\) 2NaNO\(_2\) + O\(_2\) * Products: NaNO\(_2\), O\(_2\) (2 products)
3. Decomposition of Be(NO\(_3\))\(_2\): * 2Be(NO\(_3\))\(_2\) \(\xrightarrow{\Delta}\) 2BeO + 4NO\(_2\) + O\(_2\) * Products: BeO, NO\(_2\), O\(_2\) (3 products)
Total number of products: * 3 (LiNO\(_3\)) + 2 (NaNO\(_3\)) + 3 (Be(NO\(_3\))\(_2\)) = 8 products
Therefore, the total number of products formed is 8.
Final Answer: 8.
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