Question

In the circuit shown in figure, the potential barrier for Ge diode is 0.3 V and for Si diode it is 0.7 V. What is the voltage $V_{A}$?

• A. 23.7 V
• B. 23 V
• C. 24.3 V
• D. 24.7 V

Hint:

In parallel, the "path of least resistance" (lowest barrier) dictates the circuit voltage.

Answer 1

The Correct Option is A

Step 1: Concept
In a parallel diode configuration, the diode with the lower barrier voltage will conduct first, clamping the voltage across the other diode.
Step 2: Analysis
Ge barrier (0.3 V) < Si barrier (0.7 V). Therefore, the Ge diode will conduct and the Si diode will remain off.
Step 3: Calculation
$V_{A} = V_{source} - V_{barrier}$. $V_{A} = 24\text{ V} - 0.3\text{ V} = 23.7\text{ V}$.
Step 4: Conclusion
Hence, the voltage $V_{A}$ is 23.7 V.
Final Answer:(A)