Question:

In the circuit given below, each of three resistors of \(4\Omega\) can have a maximum power of \(20\,\text{W}\) otherwise, it will melt. The maximum power which the whole circuit can take is: center
center

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The resistor carrying highest current usually reaches limiting power first. Check that resistor before calculating total allowable power.
Updated On: Jun 17, 2026
  • \(30\,\text{W}\)
  • \(40\,\text{W}\)
  • \(20\,\text{W}\)
  • \(10\,\text{W}\)
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The Correct Option is A

Solution and Explanation

Two \(4\Omega\) resistors are in parallel: \[ R_p=\frac{4\times4}{4+4}=2\Omega \] This combination is in series with another \(4\Omega\): \[ R_{eq}=2+4=6\Omega \] Let current through series resistor be \(I\). Power in series resistor: \[ P=I^2R \] Maximum allowed: \[ 20=I^2(4) \] \[ I^2=5 \] Total circuit power: \[ P_{total}=I^2R_{eq} \] \[ P_{total}=5\times6 =30\,\text{W} \] \[ \boxed{30\,\text{W}} \]
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