Given:
\[
C_1=2\mu F,\quad C_2=2\mu F,\quad C_3=4\mu F
\]
First combine parallel capacitors:
\[
C_{23}=C_2+C_3=2+4=6\mu F
\]
Now \(C_1\) and \(C_{23}\) are in series.
Equivalent capacitance:
\[
C_{eq}=\frac{2\times6}{2+6}
=\frac{12}{8}
=1.5\mu F
\]
Battery voltage:
\[
V=4\,\text{V}
\]
Charge in series combination:
\[
Q=C_{eq}V
\]
\[
Q=1.5\times4=6\mu C
\]
Charge on each series capacitor is same.
Hence:
\[
\boxed{Q_{C_1}=6\mu C}
\]