Given:
Power = 100 KW
Voltage = 125 V
ECE of chlorine Z = 0.367 x 10-6 kg/C
Power P = Vi
100 = 125 x i
i = \(\frac {100}{125}\)
i = 0.8 A
We know that first law of electrolysis
m = Zit
m = 0.367× 10−6 × 0.8 × 60
m = 17.616 × 10−6 kg
m = 17.616 × 10−6 x 106 mg
m = 17.6 mg
So, the correct option is (A): 17.6 mg
Two cables of copper are of equal lengths. One of them has a single wire of area of cross-section A, while other has 10 wires of cross-sectional area \(\frac{A}{10}\) each. Give their suitability for transporting A.C. and D.C.
Electrolysis is the process by which an element is decomposed and undergoes some chemical change under the influence of any electric current. The first-ever electrolysis was executed out by Sir Humphrey Davey in the year 1808. Electrolysis can occur in both Galvanic cells and Electrolytic cells.
Read More: Products of Electrolysis