Question

In photoelectric effect, the stopping potential depends upon:

• A. Intensity of incident light
• B. Frequency of incident light
• C. Distance from source
• D. Area of metal surface

Hint:

In photoelectric effect: \[ eV_0=h\nu-\phi \] Stopping potential depends on: \[ \text{frequency, not intensity} \]

Answer 1

The Correct Option is B

In the photoelectric effect, stopping potential is related to the maximum kinetic energy of emitted photoelectrons.
According to Einstein's photoelectric equation: \[ eV_0=h\nu-\phi \] where:
• \(V_0\) = stopping potential
• \(h\) = Planck's constant
• \(\nu\) = frequency of incident light
• \(\phi\) = work function of metal
Step 1: Observe the relation
From the equation: \[ V_0\propto \nu \] Thus stopping potential depends on: \[ \text{frequency of incident light} \]
Step 2: Analyze other quantities
• Intensity affects photocurrent, not stopping potential.
• Distance from source does not directly determine stopping potential.
• Area of metal surface affects number of emitted electrons only. Hence: \[ \boxed{ \text{Stopping potential depends on frequency} } \] Option analysis:
• Option (A): Incorrect
• Option (B): Correct
• Option (C): Incorrect
• Option (D): Incorrect Therefore: \[ \boxed{\text{(B)}} \]