Question:
In leaching alumina, concentrated solution of \(X\) and in leaching gold, dilute solution of \(Y\) are used as leaching agents. \(X\) and \(Y\) respectively are
In leaching alumina, concentrated solution of \(X\) and in leaching gold, dilute solution of \(Y\) are used as leaching agents. \(X\) and \(Y\) respectively are
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Bayer process uses NaOH for bauxite, whereas cyanide process uses KCN/NaCN for gold extraction.
Updated On: Jun 18, 2026
- KCN, NaOH
- NaOH, KCN
- \(Ca(OH)_2\), NaCN
- NaCl, KCN
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The Correct Option is B
Solution and Explanation
Concept:
Leaching is a process in which the desired metal ore is dissolved selectively in a suitable reagent.
Step 1: Leaching of alumina.
In Bayer's process, bauxite is treated with concentrated sodium hydroxide. \[ Al_2O_3 + 2NaOH + 3H_2O \rightarrow 2Na[Al(OH)_4] \] Hence, \[ X=NaOH \]
Step 2: Leaching of gold.
Gold is extracted using dilute potassium cyanide solution. \[ 4Au+8KCN+O_2+2H_2O \rightarrow 4K[Au(CN)_2]+4KOH \] Therefore, \[ Y=KCN \] Thus, \[ \boxed{X=NaOH,\;Y=KCN} \]
Step 1: Leaching of alumina.
In Bayer's process, bauxite is treated with concentrated sodium hydroxide. \[ Al_2O_3 + 2NaOH + 3H_2O \rightarrow 2Na[Al(OH)_4] \] Hence, \[ X=NaOH \]
Step 2: Leaching of gold.
Gold is extracted using dilute potassium cyanide solution. \[ 4Au+8KCN+O_2+2H_2O \rightarrow 4K[Au(CN)_2]+4KOH \] Therefore, \[ Y=KCN \] Thus, \[ \boxed{X=NaOH,\;Y=KCN} \]
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