Step 1: Understanding k-means clustering.
In the k-means algorithm, the value of k represents the number of clusters. The minimum value of k is 1, which means all data points are grouped into a single cluster. The maximum value of k is n, where each data point forms its own cluster.
Step 2: Analysis of options.
- (A) Minimum value of k=1, maximum value of k=n/2: Incorrect, the maximum number of clusters can be n, not n/2.
- (B) Minimum value of k=1, maximum value of k=n: Correct, the minimum is 1 cluster and the maximum is n clusters.
- (C) Minimum value of k=n/2, maximum value of k=n: Incorrect, the minimum value is not n/2 but 1.
- (D) Minimum value of k=2, maximum value of k=n: Incorrect, the minimum value can be 1, not 2.
Step 3: Conclusion.
The correct answer is (B) Minimum value of k=1, maximum value of k=n.
Find the least upper bound and greatest lower bound of \( S = \{X, Y, Z\} \) if they exist, of the poset whose Hasse diagram is shown below:
Suppose \( D_1 = (S_1, \Sigma, q_1, F_1, \delta_1) \) and \( D_2 = (S_2, \Sigma, q_2, F_2, \delta_2) \) are finite automata accepting languages \( L_1 \) and \( L_2 \), respectively. Then, which of the following languages will also be accepted by the finite automata:
(A) \( L_1 \cup L_2 \)
(B) \( L_1 \cap L_2 \)
(C) \( L_1 - L_2 \)
(D) \( L_2 - L_1 \)
Choose the correct answer from the options given below: