Question:

In how many ways, can a student choose a program of 5 courses, if 9 courses are available and 2 specific courses are compulsory for every student?

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If some items are fixed, reduce the problem to selecting remaining items using combinations.
Updated On: Apr 23, 2026
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The Correct Option is C

Solution and Explanation

Concept: Use combinations when order does not matter.

Step 1:
2 courses are compulsory. So remaining choices: \[ 5 - 2 = 3 \]

Step 2:
Remaining courses available: \[ 9 - 2 = 7 \]

Step 3:
Number of ways: \[ {7 \choose 3} = 35 \] Final Answer: \[ 35 \]
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