
Given: \(∠\)POY= 90° and a: b = 2: 3.

Let the common ratio between a and b be x.
∴ XY is a straight line, rays OM and OP stand on it.
∴\(∠\)POY = \(∠\)POX = 90°
\(∠\)POX = ∠POM + \(∠\)MOX
90° = a + b
Now, a = 2x and b = 3x
\(⇒ \)a + b = 90°
2x + 3x = 90°
5x = 90°
x = \(\frac{90°}{5}\) = 18°
a = 2x = 2 \(×\) 18°
a = 36°
b = 3x = 3 × 18°
b = 54°
Also, \(∠\)MOY= \(∠\)MOP + \(∠\)POY
= a + 90°
= 36° + 90° = 126°
∴ c = 126º
Length (in hours) | Number of lamps |
|---|---|
300 − 400 | 14 |
400 − 500 | 56 |
500 − 600 | 60 |
600 − 700 | 86 |
700 − 800 | 74 |
800 − 900 | 62 |
900 − 1000 | 48 |
(i) Represent the given information with the help of a histogram.
(ii) How many lamps have a lifetime of more than 700 hours?
Why was Santosh sent to the local school?