In Dumas' method for estimation of nitrogen, 0.5 gram of an organic compound gave 60 mL of nitrogen collected at 300 K temperature and 715 mm Hg pressure. The percentage composition of nitrogen in the compound (Aqueous tension at $300 \mathrm{~K}=15 \mathrm{~mm} \mathrm{Hg}$ ) is___________%.
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- 20.87
- 12.57
- 1.257
- 18.67
The Correct Option is B
Solution and Explanation
Volume at STP: $V_0 = \frac{700 \times 60 \times 273}{760 \times 300} = 50.3$ mL.
Mass of nitrogen $= \frac{28}{22400} \times 50.3 = 0.0629$ g.
Percentage of nitrogen $= \frac{0.0629}{0.5} \times 100 = 12.57\%$.
The correct option is (2).
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