Question

Consider the following sequence of reactions to give the major product (X). P g of the major product (X) formed is reacted with NaHCO₃ solution to liberate a gas which occupied 11.2 dm³ at STP. P = ______ g.

Answer 1

Correct Answer: 61

Step 1: Understanding the Concept:
Carboxylic acids react with sodium bicarbonate (\(NaHCO_3\)) to release \(CO_2\) gas. One mole of a mono-carboxylic acid group produces one mole of \(CO_2\).

Step 2: Key Formula or Approach:
1. Moles of \(CO_2\) = \(\frac{\text{Volume at STP}}{22.4 \text{ L/mol}}\).
2. Mass = Moles \(\times\) Molar Mass.

Step 3: Detailed Explanation:
1. Calculate moles of gas:
\[ n = \frac{11.2 \text{ L}}{22.4 \text{ L/mol}} = 0.5 \text{ mol} \] 2. Based on standard reaction sequences for this problem (e.g., Toluene oxidation), the major product (X) is Benzoic Acid (\(C_6H_5COOH\)).
3. Molar mass of Benzoic Acid = \(77 + 12 + 32 + 1 = 122 \text{ g/mol}\).
4. Mass \(P = 0.5 \text{ mol} \times 122 \text{ g/mol} = 61 \text{ g}\).

Step 4: Final Answer:
The value of P is 61.