In comparison to a 0.01 M solution of glucose, the depression in freezing point of a 0.01 M MgCl2 solution is ________ .
About six times
About twice
About three times
The same
The depression in freezing point (ΔTf) of a solution is given by the formula:
ΔTf = i * Kf * m
where:
For nonelectrolyte solutions like glucose, which do not dissociate in water, the van’t Hoff factor i = 1. Thus, for a 0.01 M glucose solution:
ΔTf (glucose) = 1 * Kf * 0.01
MgCl2, however, dissociates into three ions in solution (Mg2+ and 2 Cl-), so the van’t Hoff factor i = 3. For a 0.01 M MgCl2 solution:
ΔTf (MgCl2) = 3 * Kf * 0.01
Thus, the depression in freezing point for MgCl2 is three times that of the glucose solution:
ΔTf (MgCl2) = 3 * ΔTf (glucose)
Therefore, the correct answer is: About three times.
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