Step 1: Understanding the Concept:
For an ideal transformer, power input equals power output ($V_p I_p = V_s I_s$). This leads to the relationship: $\frac{I_p}{I_s} = \frac{N_s}{N_p}$.
Step 2: Detailed Explanation:
Given: $N_p = 100$, $N_s = 200$, $I_s = 5$ A.
$$\frac{I_p}{5} = \frac{200}{100}$$
$$\frac{I_p}{5} = 2 \implies I_p = 10 \text{ A}$$
Step 3: Final Answer:
The input current is 10 A.