Question

In an experiment on photoelectric effect photons of wavelength 300 nm eject electrons from a metal of work function 2.25 eV. A photon of energy equal to that of the most energetic electron corresponds to the following transition in the hydrogen atom:

• A. \( n = 2 \) to \( n = 1 \) state
• B. \( n = 3 \) to \( n = 1 \) state
• C. \( n = 3 \) to \( n = 2 \) state
• D. \( n = 4 \) to \( n = 3 \) state

Hint:

The energy of a photon corresponds to the energy difference between the two quantum states in the hydrogen atom.

Answer 1

The Correct Option is C

Step 1: Photon energy.
The energy of the photon required to eject an electron is related to the transition in the hydrogen atom by the energy difference between the two states. For a photon energy of 2.25 eV, the corresponding transition is from \( n = 3 \) to \( n = 2 \).
Thus, the correct answer is (3).