Concept:
For an AM wave,
\[
m=\frac{V_m}{V_c},
\]
where
\[
m=\text{modulation index},
\quad
V_m=\text{peak message voltage},
\quad
V_c=\text{carrier peak voltage}.
\]
The amplitude of each sideband is
\[
V_{SB}=\frac{mV_c}{2}.
\]
The upper and lower sidebands have equal amplitudes.
Step 1: Calculate the carrier amplitude.
Given,
\[
m=0.8,
\qquad
V_m=10\,\text{V}.
\]
Using
\[
m=\frac{V_m}{V_c},
\]
\[
0.8=\frac{10}{V_c}.
\]
\[
V_c=\frac{10}{0.8}.
\]
\[
V_c=12.5\,\text{V}.
\]
Step 2: Find the amplitude of each sideband.
\[
V_{SB}
=
\frac{mV_c}{2}.
\]
\[
V_{SB}
=
\frac{0.8\times12.5}{2}.
\]
\[
V_{SB}
=
\frac{10}{2}.
\]
\[
V_{SB}=5\,\text{V}.
\]
Step 3: Write the amplitudes of USB and LSB.
\[
V_{USB}=5\,\text{V},
\]
\[
V_{LSB}=5\,\text{V}.
\]
Step 4: Write the final answer.
\[
\boxed{V_{USB}=5\,\text{V},\quad V_{LSB}=5\,\text{V}}
\]
\[
\boxed{\text{Answer = (C)}}
\]