Question:
In a three-component system of phase equilibria, the maximum number of degrees of freedom can be: (use the phase rule \(F = C - P + 2\), with the minimum number of phases \(P = 1\))
In a three-component system of phase equilibria, the maximum number of degrees of freedom can be: (use the phase rule \(F = C - P + 2\), with the minimum number of phases \(P = 1\))
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Degrees of freedom are maximum when the number of phases is minimum, P=1.
Updated On: Jul 3, 2026
- 4
- 3
- 2
- 1
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The Correct Option is A
Solution and Explanation
Step 1: F=C-P+2.
Step 2: C=3, minimum P=1.
Step 3: F=3-1+2=4.
\[\boxed{F_{max} = 4}\]Was this answer helpful?
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