Question:

In a school drill, a number of children are asked to stand in a circle. They are evenly spaced and the 6th child is diametrically opposite the 16th child. How many children are made to stand in the circle?

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On an evenly spaced circle of \(N\) people, two positions are diametrically opposite exactly when they differ by \(N/2\).
Updated On: Jul 14, 2026
  • 16
  • 20
  • 22
  • None of these
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The Correct Option is B

Solution and Explanation

Step 1: Understand what "diametrically opposite" means on an evenly spaced circle.
If \(N\) children stand evenly spaced around a circle and are numbered in order, two children are diametrically opposite each other exactly when their position numbers differ by half the total count, \(\frac{N}{2}\). This is because going halfway around the circle from any position lands exactly on the point directly across from it.

Step 2: Apply this to the 6th and 16th children.
The two children given as diametrically opposite are at positions 6 and 16. Their difference is
\[ 16 - 6 = 10 \]

Step 3: Set this equal to half the total.
\[ \frac{N}{2} = 10 \]

Step 4: Solve for \(N\).
\[ N = 20 \]

Final Answer:
20 children are needed so that the 6th and the 16th, exactly 10 apart, land directly across the circle from each other.
\[ \boxed{20} \]
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