In a row of twelve boys, a boy is shifted by three places towards the right, then he became sixth from the right end. The earlier position of that boy from the left end of the row is
Let the boy be in position \( x \) initially. After being shifted by 3 places, he becomes the sixth from the right, so his new position is \( 12 - 6 + 1 = 7 \). Since he shifted 3 places towards the right, his initial position was: \[ 7 - 3 = 4 \] Thus, the boy was initially in the fourth position from the left end. To solve position shifting problems, calculate the new position and then work backwards to find the initial position.