Step 1: Understanding the Concept:
When \(A\) beats \(B\) by \(x\) meters in a race of length \(L\), it means when \(A\) covers \(L\), \(B\) covers \((L-x)\). The ratio of their speeds is \(\frac{V_A}{V_B} = \frac{L}{L-x}\).
Step 2: Key Formula or Approach:
Use the relationship \(\frac{V_A}{V_C} = \frac{V_A}{V_B} \times \frac{V_B}{V_C}\).
Step 3: Detailed Explanation:
Let the race length be \(L\).
1. \(A\) beats \(B\) by \(30\)m: \(\frac{V_A}{V_B} = \frac{L}{L-30}\).
2. \(B\) beats \(C\) by \(20\)m: \(\frac{V_B}{V_C} = \frac{L}{L-20}\).
3. \(A\) beats \(C\) by \(48\)m: \(\frac{V_A}{V_C} = \frac{L}{L-48}\).
Combining these:
\[ \frac{L}{L-48} = \frac{L}{L-30} \times \frac{L}{L-20} \implies \frac{1}{L-48} = \frac{L}{(L-30)(L-20)} \]
\[ (L-30)(L-20) = L(L-48) \]
\[ L^2 - 50L + 600 = L^2 - 48L \]
\[ 2L = 600 \implies L = 300 \text{ meters.} \]
So, Statement I is true.
4. Checking speed ratios:
Speed of \(A = V_A = \text{constant} \times 300\).
Speed of \(B = V_B = \text{constant} \times (300-30) = 270\).
Speed of \(C\): Since \(\frac{V_B}{V_C} = \frac{300}{280}\), then \(V_C = V_B \times \frac{280}{300} = 270 \times \frac{28}{30} = 9 \times 28 = 252\).
Ratio \(V_A : V_B : V_C = 300 : 270 : 252\).
Dividing by \(6\): \(50 : 45 : 42\).
Since the ratio in Statement II is \(50:45:40\), Statement II is false.
Step 4: Final Answer:
Statement I is true, but Statement II is false.