Question:

In a population, the frequency of an allele changes with time as shown in the table below.
Year (x)010203040
Allele frequency (y)0.10.20.30.40.5
Which one of the following describes how allele frequency changes with year?

Show Hint

Find the slope from any two points in the table, then check which equation matches both the slope and the intercept.
Updated On: Jul 20, 2026
  • \(y = 0.01x + 0.1\)
  • \(x = y + 0.1\)
  • \(x = 0.1 + 0.01y\)
  • \(y = x + 0.1\)
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The Correct Option is A

Solution and Explanation

Step 1: Read off the points from the table.
The table gives pairs of (year, allele frequency):
\[ (0,\,0.1),\ (10,\,0.2),\ (20,\,0.3),\ (30,\,0.4),\ (40,\,0.5) \]

Step 2: Check if the points fall on a straight line.
Look at how much \(y\) changes each time \(x\) increases by \(10\):
\[ 0.2-0.1=0.1,\quad 0.3-0.2=0.1,\quad 0.4-0.3=0.1,\quad 0.5-0.4=0.1 \]
Since \(y\) goes up by the same amount, \(0.1\), every time \(x\) goes up by \(10\), the points lie on a straight line.

Step 3: Find the slope.
\[ \text{slope}=\frac{\Delta y}{\Delta x}=\frac{0.1}{10}=0.01 \]

Step 4: Find the intercept.
At \(x=0\), the table gives \(y=0.1\). Since the line has the form \(y=mx+c\), plugging in \(x=0\) gives \(c=0.1\) directly.

Step 5: Write the full equation and check it.
\[ y=0.01x+0.1 \]
Check with \(x=40\):
\[ y=0.01(40)+0.1=0.4+0.1=0.5 \]
This matches the table exactly.

Step 6: Rule out the other options.
\(x=y+0.1\) and \(x=0.1+0.01y\) both write \(x\) as a function of \(y\) with the wrong scaling, and fail when checked against the table, for example at \(y=0.1\), \(x=y+0.1\) gives \(x=0.2\), not \(0\). \(y=x+0.1\) fails too, since at \(x=0\) it gives \(y=0.1\) correctly but at \(x=10\) it wrongly gives \(y=10.1\) instead of \(0.2\).

Step 7: Final answer.
\[ \boxed{y=0.01x+0.1} \]
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