Question:
In a loop, EMF \(= 10\,\text{V}\) and total resistance \(= 5\,\Omega\). Current in circuit is:
In a loop, EMF \(= 10\,\text{V}\) and total resistance \(= 5\,\Omega\). Current in circuit is:
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For a single-loop circuit, always remember that the current remains constant at every point in the loop, and can be found by dividing the net EMF by the net series resistance.
Updated On: May 21, 2026
- $1\text{ A}$
- $2\text{ A}$
- $5\text{ A}$
- $10\text{ A}$
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Question:
The question asks to find the electric current flowing through a closed circuit loop of known total resistance connected to an electromotive force (EMF) source.
Step 2: Key Formula or Approach:
For a simple closed loop, Ohm's law (or Kirchhoff's Loop Rule) relates current ($I$), EMF ($V$), and total resistance ($R$):
\[ I = \frac{V}{R} \]
Step 3: Detailed Explanation:
• Let us identify the given parameters:
Electromotive force of the source, $\text{EMF} = 10\text{ V}$
Total loop resistance, $R = 5\ \Omega$
• According to Ohm's Law, the steady current flowing in a circuit is directly proportional to the applied voltage and inversely proportional to the resistance of the path.
• Substituting the values into the formula:
\[ I = \frac{10}{5} \] \[ I = 2\text{ A} \]
• Thus, a steady current of $2\text{ A}$ flows through the circuit loop.
Step 4: Final Answer:
The electric current flowing in the circuit is $2\text{ A}$.
The question asks to find the electric current flowing through a closed circuit loop of known total resistance connected to an electromotive force (EMF) source.
Step 2: Key Formula or Approach:
For a simple closed loop, Ohm's law (or Kirchhoff's Loop Rule) relates current ($I$), EMF ($V$), and total resistance ($R$):
\[ I = \frac{V}{R} \]
Step 3: Detailed Explanation:
• Let us identify the given parameters:
Electromotive force of the source, $\text{EMF} = 10\text{ V}$
Total loop resistance, $R = 5\ \Omega$
• According to Ohm's Law, the steady current flowing in a circuit is directly proportional to the applied voltage and inversely proportional to the resistance of the path.
• Substituting the values into the formula:
\[ I = \frac{10}{5} \] \[ I = 2\text{ A} \]
• Thus, a steady current of $2\text{ A}$ flows through the circuit loop.
Step 4: Final Answer:
The electric current flowing in the circuit is $2\text{ A}$.
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