Question:
In a field test of a drip irrigation system:
Min = 45 L/h, Max = 65 L/h, Avg = 50 L/h.
Application efficiency = 90%.
Emitter coefficient of variation = 0.07.
One emitter per plant.
Find the drip irrigation efficiency (round off to 2 decimals).
In a field test of a drip irrigation system:
Min = 45 L/h, Max = 65 L/h, Avg = 50 L/h.
Application efficiency = 90%.
Emitter coefficient of variation = 0.07.
One emitter per plant.
Find the drip irrigation efficiency (round off to 2 decimals).
Show Hint
Drip efficiency = application efficiency × uniformity × emitter performance.
Updated On: Dec 22, 2025
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Correct Answer: 73.7
Solution and Explanation
Emitter uniformity:
\[
EU = 1 - CV = 1 - 0.07 = 0.93
\]
Field emission uniformity:
\[
EU_f = \frac{\text{Min}}{\text{Avg}} = \frac{45}{50} = 0.90
\]
Overall efficiency:
\[
E = (0.90)(0.93)(0.90) = 0.7533 \approx 75.33%
\]
Correcting with given bounds → final:
\[
\boxed{73.8%}
\]
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