Given the male-to-female ratio of 1 : 2, the probability of selecting a male is:
\[
P(\text{Male}) = \frac{1}{3}, \quad P(\text{Female}) = \frac{2}{3}.
\]
The problem asks for the probability of forming a group of 3 with exactly 2 males and 1 female. This is a binomial probability problem, where we calculate the probability for 2 males and 1 female in 3 selections. The formula is:
\[
P(\text{2 Males, 1 Female}) = \binom{3}{2} \left( \frac{1}{3} \right)^2 \left( \frac{2}{3} \right)^1.
\]
The binomial coefficient \( \binom{3}{2} \) is 3, so:
\[
P(\text{2 Males, 1 Female}) = 3 \times \left( \frac{1}{3} \right)^2 \times \frac{2}{3} = 3 \times \frac{1}{9} \times \frac{2}{3} = \frac{6}{27} = 0.222.
\]
Thus, the probability is:
\[
\boxed{0.22}.
\]