Question

In a certain code language, “PENCIL” is written as “QFODJM”. How will “MARKER” be written in that code?

• A. NBSLFS
• B. NBSJFS
• C. NCSLFS
• D. NARKFS

Hint:

To eliminate choices quickly, check the first two letters and the last letter: $\text{M}\rightarrow\text{N}$, $\text{A}\rightarrow\text{B}$, and $\text{R}\rightarrow\text{S}$. This tells you the code must start with "NB..." and end with "...S". This quickly narrows down your options and confirms choice (a)!

Answer 1

The Correct Option is A

Step 1: Understanding the Concept:
Letter coding-decoding puzzles rely on systematic structural transformations along the alphabetic index sequence. To decode the encryption blueprint, we map each individual letter of the example word to its coded counterpart and measure the directional shift step value.

Step 2: Key Formula or Approach:
Analyze the letter shift behavior from the reference example: $$\text{Letter}_{\text{Coded}} = \text{Letter}_{\text{Original}} + n$$ Determine the index shift step value ($n$), then map out the target word using the identical shift rule.

Step 3: Detailed Explanation:
Let's inspect the letter shifts inside the reference pattern PENCIL $\rightarrow$ QFODJM: $\text{P} \xrightarrow{+1} \text{Q}$ $\text{E} \xrightarrow{+1} \text{F}$ $\text{N} \xrightarrow{+1} \text{O}$ $\text{C} \xrightarrow{+1} \text{D}$ $\text{I} \xrightarrow{+1} \text{J}$ $\text{L} \xrightarrow{+1} \text{M}$ The coding pattern shifts every letter forward by exactly one position ($+1$ linear progression). Now, execute this identical $+1$ shift rule across all letters of the word MARKER: $\text{M} \xrightarrow{+1} \text{N}$ $\text{A} \xrightarrow{+1} \text{B}$ $\text{R} \xrightarrow{+1} \text{S}$ $\text{K} \xrightarrow{+1} \text{L}$ $\text{E} \xrightarrow{+1} \text{F}$ $\text{R} \xrightarrow{+1} \text{S}$ Combining the resulting sequence of characters yields the coded word NBSLFS. This matches the text given in option (a).

Step 4: Final Answer:
The word MARKER will be written as NBSLFS.