Step 1: Understanding the Question:
The question requires us to decipher the pattern used to convert plaintext words to ciphertext codes and apply the same pattern to encode the word "MODEL".
Step 2: Key Formula or Approach:
We will map each letter of the alphabet to its numerical position ($A = 1, B = 2, \dots, Z = 26$) and analyze the transformation rule using the concept of opposite letter pairs.
The opposite position of letter $X$ is given by $27 - \text{position}(X)$.
Step 3: Detailed Explanation:
Let us evaluate the coding pattern for the word "INNER":
• Write the alphabetical positions of "INNER": $I=9, N=14, N=14, E=5, R=18$.
• Write the alphabetical positions of "SNNWJ": $S=19, N=14, N=14, W=23, J=10$.
• Let us analyze the sum of the positions of the letters in "INNER" and their corresponding code letters:
- $9 + 19 = 28 \implies \text{Code} = 28 - \text{Plaintext Position}$
- $14 + 14 = 28 \implies \text{Code} = 28 - \text{Plaintext Position}$
- $14 + 14 = 28 \implies \text{Code} = 28 - \text{Plaintext Position}$
- $5 + 23 = 28 \implies \text{Code} = 28 - \text{Plaintext Position}$
- $18 + 10 = 28 \implies \text{Code} = 28 - \text{Plaintext Position}$
• This indicates the code letter is the reverse opposite letter plus $1$ (since Opposite $+ 1 = 27 - P + 1 = 28 - P$).
• Let us verify this rule on "GLASS" ($G=7, L=12, A=1, S=19, S=19$):
- $G (7) \rightarrow 28 - 7 = 21$ (U).
- $L (12) \rightarrow 28 - 12 = 16$ (P).
- $A (1) \rightarrow 28 - 1 = 27 \equiv 1$ (A).
- $S (19) \rightarrow 28 - 19 = 9$ (I).
- $S (19) \rightarrow 28 - 19 = 9$ (I).
The code matches "UPAII".
• Now, apply this rule to the word "MODEL" ($M=13, O=15, D=4, E=5, L=12$):
- $M (13) \rightarrow 28 - 13 = 15$ (O).
- $O (15) \rightarrow 28 - 15 = 13$ (M).
- $D (4) \rightarrow 28 - 4 = 24$ (X).
- $E (5) \rightarrow 28 - 5 = 23$ (W).
- $L (12) \rightarrow 28 - 12 = 16$ (P).
The coded word is OMXWP.
Step 4: Final Answer:
Applying the pattern, the word 'MODEL' is written as 'OMXWP', which matches option (B).