Question:
If Young's double slit experiment is done in air first and then if the experiment is conducted by immersing the apparatus in water, the fringe width:
If Young's double slit experiment is done in air first and then if the experiment is conducted by immersing the apparatus in water, the fringe width:
Show Hint
Fringe width is directly proportional to refractive index of the medium (indirectly via $\lambda$).
Updated On: Jun 6, 2026
- remains same
- decreases
- increases
- Becomes zero
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The Correct Option is B
Solution and Explanation
Step 1: Concept
Fringe width $w = \frac{\lambda D}{d}$.
Step 2: Meaning
In water, wavelength $\lambda' = \lambda / \mu$.
Step 3: Analysis
Since $\lambda_{water} < \lambda_{air}$ (as $\mu > 1$), fringe width $w' = w / \mu < w$.
Step 4: Conclusion
The fringe width decreases.
Final Answer: (B)
Fringe width $w = \frac{\lambda D}{d}$.
Step 2: Meaning
In water, wavelength $\lambda' = \lambda / \mu$.
Step 3: Analysis
Since $\lambda_{water} < \lambda_{air}$ (as $\mu > 1$), fringe width $w' = w / \mu < w$.
Step 4: Conclusion
The fringe width decreases.
Final Answer: (B)
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