$\frac{2}{\sqrt{3}} e ^{-\frac{2 \pi }{ 3}}$
$\frac{2}{\sqrt{3}} e ^{\frac{2 \pi }{ 3}}$
$\frac{1}{\sqrt{3}} e ^{-\frac{2 \pi }{ 3}}$
$\frac{1}{\sqrt{3}} e ^{\frac{2 \pi }{ 3}}$
The correct answer is (A) : \(\frac{2}{\sqrt3}e^{-\frac{2\pi}{3}}\)
Given differential equation
\(\frac{dy}{dx}+(8+4\cot2x)y=\frac{2e^{-4x}}{\sin^22x}(2\sin2x+\cos2x)\)
\(I.F=\int_{e}(8+4\cot2x)dy=e^{8x+2log_e(\sin2x)}=e^{8x}.\sin^22x\)
Solution is
\(y(e^{8x}.\sin^22x)=\int2e^{4x}(2\sin2x+\cos2x)dx+C\)
\(\therefore y(x)=\frac{e^{-4x}}{\sin2x}\)
\(\therefore y(\frac{\pi}{6})=\frac{e^{-4\frac{\pi}{6}}}{\sin(2.\frac{\pi}{6})}\)
\(=\frac{2}{\sqrt3}e^{-\frac{2\pi}{3}}\)
Let $y=y(x)$ be the solution of the differential equation $\left(x^2-3 y^2\right) d x+3 x y d y=0, y(1)=1$.Then $6 y^2( e )$ is equal to
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A differential equation is an equation that contains one or more functions with its derivatives. The derivatives of the function define the rate of change of a function at a point. It is mainly used in fields such as physics, engineering, biology and so on.
The first-order differential equation has a degree equal to 1. All the linear equations in the form of derivatives are in the first order. It has only the first derivative such as dy/dx, where x and y are the two variables and is represented as: dy/dx = f(x, y) = y’
The equation which includes second-order derivative is the second-order differential equation. It is represented as; d/dx(dy/dx) = d2y/dx2 = f”(x) = y”.
Differential equations can be divided into several types namely