Question:

Boston is 4 hr ahead of Frankfurt and 2 hr behind India. X leaves Frankfurt at 6 p.m. on Friday and reaches Boston the next day. After waiting there for 2 hr, he leaves exactly at noon and reaches India at 1 a.m. On his return journey, he takes the same route as before, but halts at Boston for 1hr less than his previous halt there. He then proceeds to Frankfurt.
If X had started the return journey from India at 2.55 a.m. on the same day that he reached there, after how much time would he reach Frankfurt?

Show Hint

Convert all the clock times to one time zone to get the outward flying times. The return trip takes the same two flying legs plus a shorter halt.
Updated On: Nov 4, 2026
  • 25 hr
  • 24 hr
  • 26 hr
  • Data insufficient
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The Correct Option is B

Solution and Explanation

Step 1: Put all times in Frankfurt time:
Boston is 4 hr ahead of Frankfurt, and India is 2 hr ahead of Boston, so India is 6 hr ahead of Frankfurt.

Step 2: Outward flying times:
X leaves Frankfurt at 6 p.m. Friday. He leaves Boston at noon (Boston time) after a 2-hr wait, so he arrived at Boston at 10 a.m. Boston time, which is 6 a.m. Frankfurt time on Saturday. Frankfurt to Boston takes \( 18{:}00 \to 06{:}00 = 12 \) hr.
Noon in Boston is 2 p.m. in India. He reaches India at 1 a.m. India time (Sunday), so Boston to India takes \( 14{:}00 \to 25{:}00 = 11 \) hr.

Step 3: Return journey:
The route is the same, so the flying times are the same: India to Boston 11 hr, Boston to Frankfurt 12 hr. The halt at Boston is \( 2 - 1 = 1 \) hr.
Total \( = 11 + 1 + 12 = 24 \) hr.

Step 4: The start time does not matter:
The question asks for the time taken, so the departure time of 2.55 a.m. does not change the answer. X reaches Frankfurt 24 hr after leaving India.

Final Answer:
The correct option is (2): 24 hr
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