Question:

If \(X\) follows a uniform distribution on \([0, 1]\), then the variance of \(X\) is:

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Exam Tip:
For uniform distribution:
• Mean \(= \frac{a + b}{2}\).
• Variance \(= \frac{(b - a)^2}{12}\).
  • 1
  • 0
  • 1/12
  • 1/2
Show Solution
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
The uniform distribution on \([a, b]\) has constant probability density function.
For \(X \sim U(a, b)\), the variance is given by: \[ \text{Var}(X) = \frac{(b - a)^2}{12} \]

Step 2: Key Formula or Approach:

Here, \(a = 0\), \(b = 1\).
So, \[ \text{Var}(X) = \frac{(1 - 0)^2}{12} = \frac{1}{12} \]

Step 3: Detailed Explanation:

The mean of \(U(0, 1)\) is \(1/2\).
Using the formula for variance, we get \(1/12\).

Step 4: Final Answer:

Therefore, option (C) is correct.
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