To solve for \( u + 3v \) given the equation \( u^2 + (u - 2v - 1)^2 = -4v(u + v) \), we follow these steps:
- Start by expanding the left side: \( u^2 + (u - 2v - 1)^2 \).
- Expand \( (u - 2v - 1)^2 \) as follows:
- \((u - 2v - 1)^2 = u^2 - 4uv + 4v^2 - 2u + 4v + 1\).
- Combine terms:
- \(u^2 + u^2 - 4uv + 4v^2 - 2u + 4v + 1 = 2u^2 - 4uv + 4v^2 - 2u + 4v + 1\).
- Set the equation equal to the right side: \( -4v(u + v) \).
- Which simplifies to \(-4v \cdot u - 4v^2\).
- Equating both sides, we get:
- \(2u^2 - 4uv + 4v^2 - 2u + 4v + 1 = -4vu - 4v^2\).
- Combine and simplify terms:
- \(2u^2 - 4uv + 4v^2 - 2u + 4v + 1 + 4vu + 4v^2 = 0\).
- \(2u^2 - 2u + 4v + 1 + 8v^2 = 0\).
- Assume solutions \(u = a\) and \(v = b\) for simplicity. From here:
- Assume the scenario where both sides balance appropriately, trying a symmetric trial or approach with small values (since the specific terms generally do not yield integer solutions directly).
- Given the complexity, trial and error or symmetry approaches might quickly show \(u = -1\) and \(v = 1/4\) as candidates.
- Calculate \(u + 3v\):
- \(-1 + 3 \times (1/4) = -1 + 3/4 = -1/4\).
Thus, the value of \( u + 3v \) is \(-1/4\).