Concept:
If two triangles are similar, then their corresponding angles are equal.
For similar triangles:
\[
\triangle ABC \sim \triangle PQR
\]
the corresponding angles are:
\[
\angle A=\angle P
\]
\[
\angle B=\angle Q
\]
\[
\angle C=\angle R
\]
Also, the sum of angles of a triangle is:
\[
180^\circ
\]
Step 1: Use the similarity relation.
Given:
\[
\triangle ABC \sim \triangle PQR
\]
So, corresponding angles are equal:
\[
\angle B=\angle Q
\]
Given:
\[
\angle Q=83^\circ
\]
Therefore:
\[
\angle B=83^\circ
\]
Step 2: Use the angle sum property of triangle \(ABC\).
In \(\triangle ABC\):
\[
\angle A+\angle B+\angle C=180^\circ
\]
Given:
\[
\angle A=47^\circ
\]
and:
\[
\angle B=83^\circ
\]
So:
\[
47^\circ+83^\circ+\angle C=180^\circ
\]
\[
130^\circ+\angle C=180^\circ
\]
\[
\angle C=180^\circ-130^\circ
\]
\[
\angle C=50^\circ
\]
Hence, the correct answer is:
\[
\boxed{(D)\ 50^\circ}
\]