Question:

If the volume of a room is doubled and the total absorption is halved, the reverberation time will

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Reverberation time is directly proportional to volume and inversely proportional to absorption.
  • Remain unchanged
  • Be doubled
  • Become four times
  • Be halved
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The Correct Option is C

Solution and Explanation

Concept: According to Sabine's formula: \[ T=\frac{0.161V}{A} \] where \(T\) is reverberation time, \(V\) is volume of the room, and \(A\) is total absorption.

Step 1:
Original reverberation time: \[ T=\frac{0.161V}{A} \]

Step 2:
New volume is doubled: \[ V'=2V \] Total absorption is halved: \[ A'=\frac{A}{2} \]

Step 3:
New reverberation time: \[ T'=\frac{0.161V'}{A'} \] \[ T'=\frac{0.161(2V)}{\frac{A}{2}} \] \[ T'=0.161(2V)\cdot \frac{2}{A} \] \[ T'=4\left(\frac{0.161V}{A}\right) \] \[ T'=4T \] Therefore, reverberation time becomes four times: \[ \boxed{\text{Become four times}} \]
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