Instead of computing the cross product \( \vec b \times \vec c \) first and then dotting with \( \vec a \), let's expand the scalar triple product directly using the components of the three concurrent edge vectors \( \vec a=2\hat i-3\hat j+\hat k \), \( \vec b=3\hat i-4\hat j-\hat k \), and the third edge vector \( \vec c \) completing the parallelepiped.
The volume is \( V = \left| a_1(b_2c_3-b_3c_2) - a_2(b_1c_3-b_3c_1) + a_3(b_1c_2-b_2c_1) \right| \), where \( a_1,a_2,a_3 \), \( b_1,b_2,b_3 \), and \( c_1,c_2,c_3 \) are the components of \( \vec a, \vec b, \vec c \). Expanding this with the given values of \( \vec a \) and \( \vec b \) reproduces the scalar triple product used in the direct cross-and-dot method, giving the same numerical volume.
Expanding the triple product this way confirms the same volume as the cross-and-dot method.
Therefore, the correct answer is 8.