Let \( P(A) = 0.2 \) and \( P(B) = 0.3 \). We are asked to find the probability that either A or B fail. This can be expressed as \( P(A \cup B) \).
Using the formula for the union of two events:
\[
P(A \cup B) = P(A) + P(B) - P(A \cap B)
\]
Since the events A and B are independent, we have:
\[
P(A \cap B) = P(A) \times P(B) = 0.2 \times 0.3 = 0.06
\]
Now, substitute the values into the formula:
\[
P(A \cup B) = 0.2 + 0.3 - 0.06 = 0.44
\]
Thus, the correct answer is (B) 0.44.