If the potential difference across \(PQ\) is 4V, the potential difference across \(A\) and \(B\) in the given figure is:

Step 1: Analyze the circuit and use Kirchhoff's Voltage Law. Given \(PQ = 4V\), each \(60 \, \Omega\) resistor equally shares the voltage drop when combined with the \(8 \, \Omega\) resistor in parallel circuits.
Step 2: Calculate the potential difference across \(A\) and \(B\). Given the potential difference across \(PQ\), the total resistance in parallel with PQ can be considered equivalent to a voltage source of 4V extended through multiple resistors:
\[
V_{AB} = V_{PQ} + \text{additional voltage drops across similar paths}.
\]
Considering a 3:1 ratio of the entire circuit setup based on resistor arrangements:
\[
V_{AB} = 3 \times V_{PQ} = 3 \times 6V = 18V.
\]
In the given circuit, the electric currents through $15\, \Omega$ and $6 \, \Omega$ respectively are

Find the least horizontal force \( P \) to start motion of any part of the system of three blocks resting upon one another as shown in the figure. The weights of blocks are \( A = 300 \, {N}, B = 100 \, {N}, C = 200 \, {N} \). The coefficient of friction between \( A \) and \( C \) is 0.3, between \( B \) and \( C \) is 0.2 and between \( C \) and the ground is 0.1.

A truck of mass 1200 kg moves over an inclined plane raising 1 in 20, with a speed of 18 kmph. The power of the engine is
(g = 10 m/s\(^{-2}\)):
A man of mass 70 kg jumps to a height of 0.8 m from the ground, then the momentum transferred by the ground to the man is
(g = 10 m/s\(^{-2}\)):