Find the least horizontal force \( P \) to start motion of any part of the system of three blocks resting upon one another as shown in the figure. The weights of blocks are \( A = 300 \, {N}, B = 100 \, {N}, C = 200 \, {N} \). The coefficient of friction between \( A \) and \( C \) is 0.3, between \( B \) and \( C \) is 0.2 and between \( C \) and the ground is 0.1.
Find the least horizontal force \( P \) to start motion of any part of the system of three blocks resting upon one another as shown in the figure. The weights of blocks are \( A = 300 \, {N}, B = 100 \, {N}, C = 200 \, {N} \). The coefficient of friction between \( A \) and \( C \) is 0.3, between \( B \) and \( C \) is 0.2 and between \( C \) and the ground is 0.1.
Show Hint
- 60 N
- 90 N
- 80 N
- 70 N
The Correct Option is A
Solution and Explanation
Step 1: Calculate the total friction force required to overcome.
Normal force on C = 600 N (sum of all weights)
Friction force on C = 0.1 × 600 N = 60 N
Friction force between B and C = 0.2 × 100 N = 20 N
Friction force between A and C = 0.3 × 200 N = 60 N
Total friction force to overcome = 60 N + 20 N + 60 N = 140 N
Step 2: Assess the minimum force required.
To initiate motion, the applied force P must overcome the total friction force of 140 N. Thus, P must be at least 140 N.
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