Question:
If the indicated power of an IC engine at NO-LOAD condition is 0.5 kW, then the friction power is ______ kW.
If the indicated power of an IC engine at NO-LOAD condition is 0.5 kW, then the friction power is ______ kW.
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At no load the brake power is zero, so think about where the indicated power goes.
Updated On: Aug 17, 2026
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The Correct Option is C
Solution and Explanation
Step 1: Write the power balance for an IC engine.
The indicated power IP is the power developed inside the cylinder, and it splits into useful brake power BP and friction power FP: \( IP = BP + FP \).
Step 2: Apply the no-load condition.
At no load the engine drives no external load, so the output torque and the brake power are both zero: \( BP = 0 \).
Step 3: Solve for friction power.
With \( BP = 0 \), the balance gives \( FP = IP - BP = IP \), and since the indicated power at no load is 0.5 kW, the friction power also equals 0.5 kW.
Final Answer:
At no load, all the indicated power goes to overcome internal friction. \[ \boxed{FP = 0.5 \text{ kW}} \]
The indicated power IP is the power developed inside the cylinder, and it splits into useful brake power BP and friction power FP: \( IP = BP + FP \).
Step 2: Apply the no-load condition.
At no load the engine drives no external load, so the output torque and the brake power are both zero: \( BP = 0 \).
Step 3: Solve for friction power.
With \( BP = 0 \), the balance gives \( FP = IP - BP = IP \), and since the indicated power at no load is 0.5 kW, the friction power also equals 0.5 kW.
Final Answer:
At no load, all the indicated power goes to overcome internal friction. \[ \boxed{FP = 0.5 \text{ kW}} \]
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