Question:

If the function $f(x)$ is bounded and integrable on $[a,b]$ such that $f(x) \ge 0$ $\forall x \in [a,b]$, $b \ge a$ then $\int_{a}^{b} f(x) dx$ is __}

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Integration preserves inequalities: if $f(x) \ge g(x)$, then $\int f \ge \int g$.
  • $\le 0$
  • $= 0$
  • $\ge 0$
  • $x \ne 0$
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The Correct Option is C

Solution and Explanation

Step 1: Concept
This refers to the monotonicity property of the Riemann integral.

Step 2: Meaning

If the integrand $f(x)$ is non-negative throughout the interval $[a,b]$, the accumulation of its values (the integral) must also be non-negative.

Step 3: Analysis

Since $f(x) \ge 0$ for all $x$ and the interval length $(b-a)$ is non-negative, every sum used to define the integral is $\ge 0$.

Step 4: Conclusion

Therefore, the limit of these sums, $\int_{a}^{b} f(x) dx$, must be greater than or equal to 0. Final Answer: (C)
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