Question

If the elevation in boiling point of a solution of 10 g of solute (mol. wt. = 100) in 100 g of water is \( \Delta T_b \), the ebullioscopic constant of water is:

• A. \( \frac{\Delta T_b}{10} \)
• B. \( \frac{\Delta T_b}{100} \)
• C. \( \frac{10 \Delta T_b}{100} \)
• D. \( \frac{\Delta T_b}{\mu} \)

Hint:

The ebullioscopic constant can be derived by using the elevation in boiling point and other solution properties.

Answer 1

The Correct Option is A

Step 1: Formula for elevation in boiling point.
The formula for the elevation in boiling point is: \[ \Delta T_b = \frac{K_b \cdot m \cdot W}{M \cdot 100} \] where \( K_b \) is the ebullioscopic constant, \( m \) is the molality, \( W \) is the mass of the solvent, and \( M \) is the molar mass of the solute.
Thus, the correct answer is (1).