Question:
If the elevation in boiling point of a solution of 10 g of solute (mol. wt. = 100) in 100 g of water is \( \Delta T_b \), the ebullioscopic constant of water is:
If the elevation in boiling point of a solution of 10 g of solute (mol. wt. = 100) in 100 g of water is \( \Delta T_b \), the ebullioscopic constant of water is:
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The ebullioscopic constant can be derived by using the elevation in boiling point and other solution properties.
Updated On: Mar 25, 2026
- \( \frac{\Delta T_b}{10} \)
- \( \frac{\Delta T_b}{100} \)
- \( \frac{10 \Delta T_b}{100} \)
- \( \frac{\Delta T_b}{\mu} \)
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The Correct Option is A
Solution and Explanation
Step 1: Formula for elevation in boiling point.
The formula for the elevation in boiling point is: \[ \Delta T_b = \frac{K_b \cdot m \cdot W}{M \cdot 100} \] where \( K_b \) is the ebullioscopic constant, \( m \) is the molality, \( W \) is the mass of the solvent, and \( M \) is the molar mass of the solute.
Thus, the correct answer is (1).
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