Question

If the electric field between the plates of a capacitor with charge \( 2q \) is \( E \), then what will the electric field be when the capacitor is connected to a battery with a voltage \( E \) across the plates?

• A. \( E/2 \)
• B. \( E \)
• C. \( 2E \)
• D. \( 4E \)

Hint:

The electric field in a capacitor is proportional to the voltage across the plates. If the voltage doubles, the electric field doubles as well.

Answer 1

The Correct Option is C

Step 1: Understanding the electric field.
The electric field \( E \) between the plates of a capacitor is given by the formula: \[ E = \frac{V}{d} \] where: - \( V \) is the voltage across the plates, - \( d \) is the distance between the plates.
Step 2: Applying the change in voltage.
If the capacitor is connected to a battery with a voltage \( E \) across the plates, and the charge on the capacitor is \( 2q \), the electric field will double.
Step 3: Conclusion.
The electric field will become \( 2E \), so the correct answer is (C).