Step 1: Compare with standard SHM equation:
\[
x = A \cos(\omega t) \Rightarrow \omega = 125.6 \, \text{rad/s}
\]
Step 2: Use the relation between angular frequency and time period:
\[
T = \frac{2\pi}{\omega} = \frac{2\pi}{125.6}
\]
Step 3: Calculate:
\[
T \approx \frac{6.28}{125.6} \approx 0.05 \, \text{seconds}
\]
% Final Answer
\[
\boxed{0.05 \, \text{s}}
\]