Question:

If the area of a rhombus is \(24\text{ cm}^2\) and one of its diagonals is \(8\) cm, then the side of that rhombus (in cm) is

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In rhombus problems, after finding diagonals, use half-diagonals with Pythagoras theorem to find the side.
Updated On: Jul 15, 2026
  • \(5\)
  • \(6\)
  • \(4\)
  • \(\frac52\)
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The Correct Option is A

Solution and Explanation

Concept: Area of a rhombus: \[ A=\frac12 d_1d_2 \] where \(d_1,d_2\) are diagonals. Also, diagonals bisect each other at right angles.

Step 1:
Find the second diagonal.
Given: \[ A=24 \] \[ d_1=8 \] So: \[ 24=\frac12(8)(d_2) \] \[ 24=4d_2 \] \[ d_2=6 \]

Step 2:
Use half diagonals to form a right triangle.
Half diagonals: \[ \frac{8}{2}=4 \] \[ \frac{6}{2}=3 \] Side of rhombus: \[ =\sqrt{4^2+3^2} \] \[ =\sqrt{16+9} \] \[ =\sqrt{25} \] \[ =5 \] Thus, the side of the rhombus is: \[ \boxed{5} \]
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